Question

You release a ball from rest at the top of a ramp. 6 s later it is moving at 4.0
m/s. What is the acceleration? (in meters per second squared) *
Your answer

Answer 1

$a = \frac{vf - vi}{t}$

here initial velocity vi=0 as ball release from rest

the final velocity is vf=4.0

time is t=6

so putting all these values in above equation

$a = \frac{ 4.0- 0}{6}$

$a = 0.6667m \s {}^{2}$