Answer:
Area = 16 cm²
Perimeter = 20.9 cm
Step-by-step explanation:
To find the perimeter and area of the given triangle length of all sides of the given triangle will be required.
Use the formula to determine the distance between two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex],
d = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Distance between A(0,9) and B(4, 9),
AB = [tex]\sqrt{(4-0)^2+(9-9)^2}[/tex] = 4 cm
Distance between A(0,9) and C(0, 1),
AC = [tex]\sqrt{(0-0)^2+(9-1)^2}[/tex]
AC = 8 cm
Distance between B(4, 9) and C(0, 1),
BC = [tex]\sqrt{(4-0)^2+(9-1)^2}[/tex]
BC = [tex]\sqrt{16+64}[/tex]
= [tex]\sqrt{80}[/tex]
= [tex]4\sqrt{5}[/tex]
= 8.9 cm
Area of ΔABC = [tex]\frac{1}{2}(\text{AC})(\text{AB})[/tex]
= [tex]\frac{1}{2}(8)(4)[/tex]
= 16 cm²
Perimeter of the triangle = AB + AC + BC
= 4 + 8 + 8.9
= 20.9 cm
