Question

the value of x in logx(9/63)=1/2 is​

Answer 1

Answer: x = 7/2

Step-by-step explanation: u juss simplify 1/2 x 7 to 7/2 so x = 7/2

Answer 2

The value of x in logarithmic equation $log_{10}x(\frac{9}{63} )=\frac{1}{2}$ is $1000\sqrt{10}$.

What is a logarithmic equation?

"A logarithmic equation is an equation that involves the logarithm of an expression containing a variable."

Given logarithmic equation

$log_{10}x(\frac{9}{63} )=\frac{1}{2}$

⇒ $log_{10}x(\frac{1}{7} )=\frac{1}{2}$

⇒ $log_{10}x=\frac{1}{2}({7} )$

⇒ $log_{10}x=\frac{7}{2}$

⇒ $x = 10^{\frac{7}{2} }$

⇒ $x = 10^{3+\frac{1}{2} }$

⇒ $x = 10^{3}$ × $10^{\frac{1}{2} }$

⇒ $x = 1000\sqrt{10}$

The value of  $x = 1000\sqrt{10}$

Hence, the value of x in logarithmic equation $log_{10}x(\frac{9}{63} )=\frac{1}{2}$ is $1000\sqrt{10}$.

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