Answer:
It will tale 1 hour before they meet and they will meet agin at 9 :00 AM.
Step-by-step explanation:
Speed of Jane, [tex]v_1=3[/tex] mph
and the speed of Jillian, [tex]v_2= 5[/tex] mph.
Length of one complete circle = 8 miles.
Both are moving in the opposite direction, let the starting point is at O, and met at the point P after time, t, as shown in the figure.
Let the length covered by Jane via path OAP= x miles.
[tex]\Rightarrow x= 3t[/tex] [as distance= speed x time]
[tex]\Rightarrow t=x/3 \cdots(i)[/tex]
The length covered by Jillian via path OBP [tex]= 8-x[/tex] miles
[tex]\Rightarrow 8-x= 5t[/tex] [as distance = speed x time]
[tex]\Rightarrow t=(8-x)/5 \cdots(i)[/tex]
Now from equation (i) and (ii),
[tex]\frac{x}{3} = \frac{8-x}{3}[/tex]
[tex]\Rightarrow 5x=3(8-x)[/tex]
[tex]\Rightarrow 5x+3x=24[/tex]
[tex]\Rightarrow x=3[/tex]
So, the distanc covered by Jane = 3 miles and
the distanc covered by Jillian = 8-3=5 miles
From equation (i), time taken, t = 3/3= 1 hour.
So, it will tale 1 hour before they meet.
As the startion time was 8:00 AM, so the will agin meet at 9 :00 AM.