Answer:
(a) 14.5 m/s
(b) 9.5 m/s
Explanation:
Let the speed of the boat in the still water (i.e relative to ground) is [tex]v_0[/tex].
Given that the speed of the boat relative to water, [tex]v_r=12.0[/tex] m/s.
Speed of the water current of the river relative to the ground, [tex]u_0=2.50[/tex] m/s towards east.
(a) When the boat is heading toward the east (in the same direction of the current of the river)
The relative velocity, [tex]v_r[/tex], of the boat with respect to ground is
[tex]v_r=v_0-u_0[/tex]
[tex]\Rightarrow 12=v_0-2.5[/tex]
[tex]\Rightarrow v_0=12+2.5=14.5[/tex] m/s
Hence, the boat's speed relative to the ground when it is heading east, with the current, is 14.5 m/s.
(b) When the boat is heading toward the west (in the opposite direction of the current of the river)
The relative velocity, [tex]v_r[/tex], of the boat with respect to ground is
[tex]v_r=v_0-(-u_0)[/tex]
[tex]\Rightarrow 12=v_0+2.5[/tex]
[tex]\Rightarrow v_0=12-2.5=9.5[/tex] m/s
Hence, the boat's speed relative to the ground when it is heading west, against the current, is 9.5 m/s.