Determine the measure of ∠Q, rounded to the nearest tenth of a degree.
images attached.

Answer:
D
Step-by-step explanation:
Using the Sine rule in Δ QRS , that is
[tex]\frac{q}{sinQ}[/tex] = [tex]\frac{r}{sinR}[/tex] , that is
[tex]\frac{15}{sinQ}[/tex] = [tex]\frac{12}{sin50.1}[/tex] ( cross- multiply )
12× sinQ = 15 × sin50.1° ( divide both sides by 12 )
sinQ = [tex]\frac{15sin50.1}{12}[/tex] , thus
Q = [tex]sin^{-1}[/tex] ( [tex]\frac{15sin50.1}{12}[/tex] ) ≈ 73.5° ( to the nearest tenth )