Answer:
12
Step-by-step explanation:
No. of red flyers = 6
No. of blue flyers = 4
We need to find the minimum number of flyers of each color if she gave out the same number of red and blue flyers. For this we must find the LCM of 6 and 4.
Prime factorization of 6 = 2×3
Prime factorization of 4 = 2×2
Lowest common multiple of 6 and 4 = 12
Hence, there are 12 minimum number of flyers of each color