The empirical formula for the compound containing 40.05 % sulfur and 59.95 % oxygen is SO₃
Data obtained from the question
- Sulphur (S) = 40.05%
- Oxygen (O) = 59.95%
- Empirical formula =?
How to determine the empirical formula
The empirical formula of the compound can be obtained as follow
Divide by their molar mass
S = 40.05 / 32 = 1.25
O = 59.95 / 16 = 3.75
Divide by the smallest
S = 1.25 / 1.25 = 1
O = 3.75 / 1.25 = 3
Thus, the empirical formula of the compound is SO₃
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