Question

A doctor gives a patient a 70% chance of surviving bypass surgery after a heart attack. If the patient
Isurvives the surgery, then the patient has a 40% chance that the heart damage will heal. Find the
probability that the patient survives the surgery and the heart damage heals. The probability is nothing

Answer 1

Answer:

The probability the person will survive the bypass surgery and that the heart damage will heal is about 28%

Step-by-step explanation:

(7/10)*(4/10)*100=28

To solve for probability of situations like this you have to multiply the fractional values of the two percentages and multiply by 100 to get the new percentage.

Answer 2

Using conditional probability, it is found that there is a 0.28 = 28% probability that the patient survives the surgery and the heart damage heals.

Conditional Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

• P(B|A) is the probability of event B happening, given that A happened.
• $P(A \cap B)$ is the probability of both A and B happening.
• P(A) is the probability of A happening.

In this problem:

• Event A: Surviving.
• Event B: Healing.
• 70% chance of surviving, thus $P(A) = 0.7$.
• If the patient survives, 40% chance of healing, thus $P(B|A) = 0.4$.

The probability of both is $P(A \cap B)$, then:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)P(A)$

$P(A \cap B) = 0.4(0.7)$

$P(A \cap B) = 0.28$

0.28 = 28% probability that the patient survives the surgery and the heart damage heals.

A similar problem is given at https://brainly.com/question/24161830