Answer:
A) d(r) = 2r
Value when r = 5 is 10 ft.
diameter is 10 ft when the radius is 5ft
B) A(r) = πr²
Value when r = 5 is 25π ft²
Area is 25π ft² when radius is 5 feet
C) C(r) = 2πr
Value when r = 5 is 10π
Circumference is 10π when radius is 5 feet
Step-by-step explanation:
A) Using function notation, since d = 2r
d(r) = 2r
d(5) = 2(5)
d(5) = 10 feet
This means that the diameter is 10 ft when the radius is 5ft
B) Area = πr²
In function notation, its;
A(r) = πr²
When radius is 5 feet,
Area is; A(5) = π(5²) = 25π
It means Area is 25π ft² when radius is 5 feet
C) Circumference is 2πr
In function notation, it's;
C(r) = 2πr
When r = 5 feet,
Circumference is;
C(5) = 2π(5)
C(5) = 10π