Question

A normal force of 38 newtons acts on a book lying on a table. If the coefficient of static friction is 1.2, what is the minimum applied force required to slide the book?

Answer 1

N = normal force = 38 newtons

Ks = coefficient of static friction = 1.2

Ff = maximum friction force = ks*N = 1.2 * 38 newtons = 45.6 newtons

F = minimum applied force = Ff

F = 45.6 newtons

Answer 2

Answer:

B,  46 newtons for Plato users

Explanation: