In a certain fraction, the denominator is 4 larger than the numerator. If 2 is added to both the numerator and the denominator,the result is 3\5. Find the original fraction. PLS ANSWER ​

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The original fraction is [tex]\frac{4}{8}[/tex]

Let the numerator = a

Let the denominator = b

Denominator is 4 larger than the numerator: b = a + 4

2 is added to both the numerator and the denominator: (a + 4 +2) and a + 2

The algebraic equation from the given statement is formed as follows;

[tex]\frac{a+ 2}{a+4+2 } = \frac{3}{5} \\\\\frac{a+ 2}{a + 6} =\frac{3}{5} \\\\5(a + 2) = 3(a + 6)\\\\5a + 10 = 3a + 18\\\\5a - 3a = 18 -10\\\\2a = 8\\\\a =4[/tex]

The original fraction is calculated as follows;

[tex]\frac{a }{a +4} = \frac{4}{4+ 4} = \frac{4}{8}[/tex]

Thus, the original fraction is [tex]\frac{4}{8}[/tex]

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