Question

QUESTION 8
Solve the problem that involves probabilities with events that are not mutually exclusive.
Consider a political discussion group consisting of 8 Democrats, 3 Republicans, and 7 Independents. Suppose that two
group members are randomly selected, in succession, to attend a political convention. Find the probability of selecting
an Independent and then a Democrat.
14/81, 25/153, 7/306/ or 4/153?

Answer 1

Answer:

Option (2).

Step-by-step explanation:

Number of Democrats in a political discussion = 8

Number of Republicans = 3

Number of independents = 7

Total members in the discussion = (8 + 3 + 7)

                                                       = 18

Probability of selecting an independent = $\frac{7}{18}$

Remaining members after selecting one independent = 17

Probability of selecting a Democrat = $\frac{8}{17}$

Probability of selecting a Republican then a Democrat = $\frac{7}{18}\times \frac{8}{17}$

                                                                                           = $\frac{28}{153}$

Therefore, Option (2) will be the answer.