Question

5. What mass of water can be heated from 15.0°C to 40.0" with 925 Joules 2 points of heat?

Answer 1

Mass of water = 8.84 g

Further explanation  

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

c of water = 4.182 J / g ° C  

Q = 925 J

mass of water :

$\tt Q=m.c.\Delta T\\\\925=m\times 4.182\times (40-15)\\\\m=8.84~g$