Question

What is the equation of the line that passes through the point (-6,-7)(−6,−7) and has a slope of 0?

Answer 1

Answer:

y = -7

Step-by-step explanation:

The equation of a line is:

y = mx + b    where m = slope

To find b, plug in a point and solve.

(-6,-7)

y = mx + b

-7 = 0(-6) + b

- 7 = 0 + b

-7 = b

So the equation is:

y = 0x + b or

y = -7

No matter what you plug into x, y = -7, because your slope is 0.

Answer 2

The equation of the line that passes through the point (-6,-7) and with slope 0  is $y=-7$.

Point through which the given line passes ≡ (-6,-7)

The slope of the line =0

What is the equation of a straight line?

The equation of a straight line passing through the point (x₁, y₁) is given by: $y-y_1 =m(x-x_1)$

where m is the slope of the line.

So, the equation of the line that passes through the point (-6,-7) and with slope 0 will be:

$y-(-7) = 0(x-(-7))$

$y+7 =0$

$y =-7$

So, the required equation of the line is y=-7.

Therefore,  the equation of the line that passes through the point (-6,-7) and with slope 0  is $y=-7$.

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