Question

2. A bird flying horizontally at 10 m/s drops a branch. The bird is flying at an altitude of 20 m. Determine
the horizontal displacement it moves relative to where it was dropped.

Answer 1

Answer:

The horizontal displacement is 20 m.

Explanation:

Given that,

Velocity = 10 m/s

Height = 20 m

We need to calculate the time

Using equation of motion

$s=ut+\dfrac{1}{2}gt^2$

Put the value into the formula

$20=0+\dfrac{1}{2}\times9.8\times t^2$

$t^2=\dfrac{20\times2}{9.8}$

$t=\sqrt{\dfrac{20\times2}{9.8}}$

$t=2.0\ sec$

We need to calculate the horizontal displacement

Using formula of horizontal displacement

$\Delta x=v_{x}\times t$

Put the value into the formula

$\Delta x=10\times2.0$

$\Delta x=20\ m$

Hence, The horizontal displacement is 20 m.