The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the dimensions of the rectangle.
d=2+20+2w=22+2w so the eqations would be l=20+2w and d=22+2w so when solving for the width, (20+2w)^2+w^2=(22+2w)^2 your equation would be : 400+80w+4w^2+w^2=484+44w+w^2 the anwer would be 1.9226
