Answer:
8 m/s².
Explanation:
We'll begin by calculating the force applied to 0.25 Kg hockey puck. This is illustrated below:
Mass (m) = 0.25 Kg
Acceleration (a) = 16 m/s²
Force (F) =.?
Force (F) = mass (m) × acceleration (a)
F = ma
F = 0.25 × 16
F = 4 N
Therefore, a force of4 N was applied to the 0.25 Kg hockey puck.
Finally, we shall determine the acceleration in which the 4 N force will give to the 0.50 Kg baseball. This can be obtained as follow:
Mass (m) = 0.50 Kg
Force (F) = 4 N
Acceleration (a) =?
F = ma
4 = 0.5 × a
Divide both side by 0.5
a = 4 / 0.5
a = 8 m/s²
Therefore, the same force (i.e 4 N) applied to the hockey puck will give the 0.5 kg baseball an acceleration of 8 m/s².
