Question

Convert the following C program to C++.

More instructions follow the code.

#include
#include

#define SIZE 5

int main(int argc, char *argv[]) {
int numerator = 25;
int denominator = 10;
int i = 0;

/*
You can assume the files opened correctly and the
correct number of of command-line arguments were
entered.
*/
FILE * inPut = fopen(argv[1], "r");
FILE * outPut = fopen(argv[2], "w");

float result = (float)numerator/denominator;
fprintf(outPut,"Result is %.2f\n", result);

float arr[SIZE];

for( ; i < SIZE; i++) {
fscanf(inPut, "%f", &arr[i]);
fprintf(outPut, "%7.4f\n", arr[i]);
}

return 0;
}

Notice this is uses command-line arguments. I have provided an input file called num.txt that will be used when running the program. The output file is called out.txt.

Make sure you are using C++ style file I/O (FILE pointers/fopen) as well as regular I/O including the C++ style output formatting (fscanf, fprintf, formatting). Also use the C++ method of casting. The lines above that are bold are the lines that you need to convert to C++. Don't forget to add the necessary C++ statements that precede the main() function.

Answer 1

Answer:

The program equivalent in C++ is:

#include <cstdio>

#include <cstdlib>

#define SIZE 5

using namespace std;

int main(int argc, char *argv[]) {

int numerator = 25;

int denominator = 10;

FILE * inPut = fopen(argv[1], "r");

FILE * outPut = fopen(argv[2], "w");

float result = (float)numerator/denominator;

fprintf(outPut,"Result is %.2f\n", result);

float arr[SIZE];

for(int i = 0; i < SIZE; i++) {

fscanf(inPut, "%f", &arr[i]);

fprintf(outPut, "%7.4f\n", arr[i]);

}

return 0;

}

Explanation:

See attachment for explanation.

Each line were numbered with equivalent line number in the C program