Question

Suppose that a car starts from rest at t = 0. The car moves with an acceleration of 1.5 m/s2. How far will the car travel in 3.0 s?

Answer 1

Answer:

6.75m

Explanation:

To calculate the distance in this question, we can use the formula:

S = ut + 1/2at^2

Where; S = distance

u = initial velocity = 0m/s

t = 3s

a = 1.5m/s^2

Hence:

S = (0 × 3) + 1/2 (1.5 × 3 × 3)

S = 0 + 1/2 (13.5)

S = 13.5/2

S = 6.75

Therefore, the car will travel 6.75m in 3seconds.

Answer 2

To find the distance traveled by the car in 3 seconds is equal to 6.75 meters.

Given the following data:

• Initial velocity = 0 m/s (since it starts from rest).

• Acceleration = 1.5 $m/s^2$

• Time = 3 seconds.

To find the distance traveled by the car in 3 seconds, we would apply the second equation of motion:

The second equation of motion.

Mathematically, the second equation of motion is given by the formula;

$S=ut +\frac{1}{2} at^2$

Where:

• S is the distance traveled.

• u is the initial velocity.

• a is the acceleration.

• t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

$S=0(3) +\frac{1}{2} \times 1.5 \times 3^2\\\\S=\frac{1}{2} \times 1.5 \times 9\\\\S = 1.5 \times 4.5$

Distance, S = 6.75 meters.

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