Question

11.
1. Calculate the number of water molecule
present in one drop of water which weighs
0.18 g.​

Answer 1

Answer:

6.022×10²¹

Explanation:

First calculate the number of moles

n=m/GFM

n=.018/18

n=0.01moles

Then multiply the number of moles by the molar mass

0.01×6.022×10²³ =6.022×10²¹