Question

What is the specific heat capacity of diamond if 64.4 J of heat is required to heat 25.0 g of diamond from 10.5°C to 15.6°C?

Answer 1

Q = mct
Q being heat in Jules
M being mass in grams
C being specific heat in J/g*C
T being the change in temperature

64.4J = 25g*c*5.1C
64.4J = (127.5g*C)*c
c = 0.505 J/g*C