Given the following equation:

4 NH_3(g) + 5 O_2(g) → 4 NO(g) + 6 H_2O(l)

How many grams of H_2O is produced if 66.60 grams of NO is produced?

Respuesta :

178.55g of H_2O are produced. When you find the molecular mass of NH_3 and O_2 and multiply them by their coefficients, you get 245.15. The law of conservation of mass states that mass can’t be created or destroyed, so this mass is the same for both the reactants and products. 245.15-66.60= 178.55. Hope this helps!
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