Answer:
Volume of gold is 9.64 L
.
Explanation:
Given data:
Mass of gold = 85 g
Temperature = standard = 273 K
Pressure = standard = 1 atm
Volume of gold = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will calculate the number of moles of gold.
Number of moles = mass/molar mass
Number of moles = 85 g/ 197 g/mol
Number of moles = 0.43
1 atm × V = 0.43 mol ×0.0821 atm.L/ mol.K × 273 K
V = 9.64 atm.L / 1 atm
V = 9.64 L
