Question

A man walks 30 m to the west than 5 m to the east in 45 seconds.

A). what is his total distance walked?
B). What is his average velocity?

Answer 1

Answer:

35 m

0.56 m/s west

Explanation:

A) Total distance is the length of the path taken.

30 m + 5 m = 35 m

B) Velocity is displacement over time.  Displacement is the difference between the final position and the initial position.

If west is -x, and east is +x, then:

Δx = -30 m + 5 m

Δx = -25 m

v = Δx / t

v = -25 m / 45 s

v = -0.56 m/s

v = 0.56 m/s west

Answer 2

The total distance travelled = 35 m and average velocity = 0.55 $m/s^{2}$

We have a man who walked 30 m to the west than 5 m to the east in 45 seconds.

We have to find out his total distance walked and his average velocity?

Define Average velocity of a body?

The average velocity is defined as the rate of change of displacement per unit time.

$v_{avg} = \frac{x_{2} -x_{1} }{t_{2} -t_{1} }$

According to the question -

A). The total distance travelled will be equal to = $X_{W} +X_{E}$ = 30 + 5 = 35m

Since, the distance travelled is a scalar quantity, we have used simple addition method.

B). In order to calculate the average velocity, first we will calculate the displacement -

Consider the direction to the west as the + x axis, then -

displacement = $30\overrightarrow{a_{x} } - 5\overrightarrow{a_{x} } = 25\overrightarrow{a_{x} }$

Magnitude of displacement = 25 x | $\overrightarrow{a_{x} }$| = 25 x 1 = 25 m

$v_{avg} = \frac{25}{45 } = 0.55$ $m/s^{2}$

Hence, the total distance travelled = 35 m and average velocity = 0.55$m/s^{2}$

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https://brainly.com/question/28149286

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