Question

A 2-column table with 5 rows. Column 1 is labeled x with entries negative StartFraction pi Over 2 EndFraction, 0, StartFraction pi Over 2 EndFraction, pi, StartFraction 3 pi Over 2 EndFraction. Column 2 is labeled y with entries 0, 6, 0, negative 6, 0.
The function represented by the table has the form y = acos(bx). Which of the following statements are true? Check all that apply.

The function increases on the interval (π, 2π).
The graph is compressed horizontally by a factor of One-half
The frequency is StartFraction 1 Over 2 pi EndFraction
The maximum value of the function is 6.
The period is π.

Answer 1

Answer:

ACD on edge2020

Step-by-step explanation:

Answer 2

The correct values function represented in the table is of y = acos(bx) are-

1. The function increases on the interval (π, 2π).
2. The frequency is StartFraction 1 Over 2 pi EndFraction ($\pi$/2)
3. The maximum value of the function is 6.

Function

What is increasing function?

A function whose value increases algebraically as the independent variable increases algebraically across some range.

What is decreasing function?

A function whose value declines as the independent variable rises over a specified range is referred to as a decreasing function.

Description for the given function:

Refer the attached table and graph.

Option (1) The function increases on the interval (π, 2π) is correct.

By graph, it is clear that the value of function is increasing between interval (π, 2π).

Option (2) The graph is compressed horizontally by a factor of One-half is incorrect.

Option (3) The frequency is StartFraction 1 Over 2 pi EndFraction is correct.

frequency = 1/time period

From the graph, time period in which function is repeating is 2π. thus frequency = 1/2π.

Option (4) The maximum value of the function is 6 is correct.

As shown in the graph, the range for the function goes up to 6.

Option (5) The period is π is incorrect.

The period for the the function is repeating is 2π not π.

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