Question

Line p passes through points (−1, 2) and (−3,−4). What is the slope of a line perpendicular to p?

Answer 1

Answer:

2/3

Step-by-step explanation:

First,  find the slope of Line P

1. Slope = rise over run ($\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$)

$\frac{2- (-4)}{-1-(-3)}$ -> $\frac{6}{-4}$

So the slope of Line P is  $\frac{6}{-4}$ or $\frac{-3}{2}$

2. Find the negative reciprocal of Line P

*the product of two lines that are perpendicular to each other is -1

negative: $\frac{3}{2}$

negative reciprocal: $\frac{2}{3}$

So the slope of the line perpendicular to Line P is 2/3.

Check:

$\frac{-3}{2}$* $\frac{2}{3}$= -1

Answer 2

The slope of the line perpendicular to the line p passing through the point (−1, 2) and (−3,−4) will be -1/3

The formula for calculating the slope of a line is expressed as:

$m = \frac{y_2-y_1}{x_2-x_1}$

If the slope of a line is "m", the slope of the line perpendicular will be -1/m

Given the coordinate points (−1, 2) and (−3,−4), we need to first get the slope of the line as shown:

$m=\frac{-4-2}{-3+1}\\m=\frac{-6}{-2}\\m = 3$

The slope of the line perpendicular to the line will be -1/3

Learn more here: https://brainly.com/question/12922257