Respuesta :
Answer:
A
Step-by-step explanation:
O = 26.6
P is a right angle so:
P = 90
angles PQO = 180
To determine Q: triangle total - (P + O)
180 - (90 + 26.6)
180 - 116.6 = 63.4
Q = 63.4
To determine side lengths: a^2 + b^2 = c^2
4^2 + b^2 = c^2
*Variable c is always hypotenuse*
Need more information so find either b or c through SOH, CAH, TOA
SOH: sine = opposite/hypotenuse
CAH: cos = adjacent/hypotenuse
TOA: tan = opposite/adjacent
tan26.6/1 = b/4
Cross multiply
1 × b = 4 × tan26.6
b = 4tan26.6
b = 2.003050791
b is about 2
b = PQ
PQ = 2
Plug b value into pythagorean theorm
4^2 + 2^2 = c^2
16 + 4 = c^2
20 = c^2
square root of 20 = square root of c^2
4.47213.... = c
c is about 4.47
c = QO
Answer:
A. ∠Q = 63.4°, PQ = 2, PQ = 4.47
Step-by-step explanation:
∠Q = 180 - 90 - 26.6
∠Q = 63.4°
side PQ
use opp. = tanФ (adj.)
PQ = tan(26.6) x 4
PQ = 2
side QO
use Pythagorean
PQ² = PO² + PQ²
PQ² = 4² + 2²
PQ = [tex]\sqrt{16 + 4}[/tex]
PQ = 4.47