Question

Find the equation of a line with a slope of 1 and passing through (11;3)

Answer 1

Step-by-step explanation:

slope(m)=(Y-Y1)/X-X1

here,

M=1

(X1,Y1)=(11,3)

NOW,

m=(Y-Y1)/(X-X1)

1=(Y-3)/(X-11)

1×(X-11)=Y-3

X-11=Y-3

X-Y-11+3=0

X-Y-8=0

X-Y=0 is the required equation.