Question

What pressure, in atm, is exerted by 2.50 L of gas containing 1.35 mol at 320 K?
14.19 atm
22.54 atm
18.42 atm
O 16.53 atm

Answer 1

Answer:

Option A = 14.19 atm

Explanation:

Given data:

Volume of gas = 2.50 L

Number of moles of gas = 1.35 mol

Temperature of gas = 320 K

Pressure of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values in formula.

P × 2.50 L =  1.35 mol × 0.0821 atm.L/ mol.K×   320

P = 35.467 atm.L/ 2.50 L

P = 14.19 atm

Thus, option A is correct.

Answer 2

The pressure in atm that should be exerted is 14.19 atm.

Calculation of the pressure:

Since

The volume of gas = 2.50 L

Number of moles of gas = 1.35 mol

Temperature of gas = 320 K

Now we know that

PV = nRT

here,

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

So,

P × 2.50 L =  1.35 mol × 0.0821 atm.L/ mol.K×   320

P = 35.467 atm.L/ 2.50 L

P = 14.19 atm

Thus, option A is correct.

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