Answer:
The horizontal distance traveled by the rock from the wall after 2 seconds is 6m.
Explanation:
Given;
initial speed of the rock, u = 3 m/s
height of the wall, h = 25 m
time of travel, t = 2 seconds
The horizontal distance is determined as follows;
X = ut + ¹/₂gt²
where;
g is acceleration due to gravity, horizontal distance is not affected by gravity, g = 0
X = ut
X = 3 x 2
X = 6 m
Therefore, the horizontal distance traveled by the rock from the wall after 2 seconds is 6m.