Answer:
The new volume is 4.15 L
Explanation:
Given
Initial Volume (,V1) = 4L
Initial Temperature (T1) = 294K
Final Temperature (T2) = 305k
Required
Determine the new volume (V2)
This will be calculated using ideal gas equation where pressure is constant.
We have
V1/T1 = V2/T2
Substitute values for V1, T1 and V2
4/294 = V2/305
Solve for V2
V2 = 305 * 4/294
V2 = 1220/294
V2 = 4.15L (approximated)