Answer:
The horizontal distance is 136.6 m.
Explanation:
Given that,
Initial speed = 38 m/s
Angle = 34°
Suppose, Calculate the horizontal distance [tex]x_{max}[/tex] in meters the ball has traveled when it returns to ground level.
We need to calculate the horizontal distance
Using formula of range
[tex]R=\dfrac{v_{0}^2\sin(2\theta)}{g}[/tex]
Where, v= speed
g = acceleration due to gravity
Put the value into the formula
[tex]R=\dfrac{(38)^2\sin(2\times34)}{9.8}[/tex]
[tex]R=136.6\ m[/tex]
Hence, The horizontal distance is 136.6 m.