Question

solve the inequality 8 < 12 + c < 12

Answer 1

Separate the inequalities by part.

$8<12+c\\12+c<12$

We'll do 8 < 12+c first then 12+c<12 next.

$8-12<c\\-4<c\\c>-4$

Then 12+c<12

$12+c<12\\c<12-12\\c<0$

Then mix c<0 and c>-4 as we'll get $-4<c<0$ #