Answer:
[tex]\boxed{x =\dfrac{87}{68}}[/tex]
Step-by-step explanation:
[tex]\dfrac{17}{3} \left(x-\dfrac{3}{2} \right) = -\dfrac{5}{4}[/tex]
Using FOIL in LHS
[tex]\dfrac{17}{3}x - \dfrac{17}{3} \cdot \dfrac{3}{2} = -\dfrac{5}{4}[/tex]
[tex]\dfrac{17}{3}x - \dfrac{51}{6} = -\dfrac{5}{4}[/tex]
[tex]\dfrac{17}{3}x = -\dfrac{5}{4}+ \dfrac{51}{6}[/tex]
[tex]\dfrac{17}{3}x = -\dfrac{5(3)}{4(3)}+ \dfrac{51(2)}{6(2)}[/tex]
[tex]\dfrac{17}{3}x = -\dfrac{15}{12}+ \dfrac{102}{12}[/tex]
Now the denominator of the fractions in the RHS are the same
[tex]\dfrac{17}{3}x = \dfrac{87}{12}[/tex]
[tex]x = \dfrac{87}{12} \cdot \dfrac{3}{17}[/tex]
[tex]x =\dfrac{261}{204} = \dfrac{87}{68}[/tex]
[tex]\boxed{x =\dfrac{87}{68}}[/tex]