Answer: E = 11.8 N/C
Explanation: Electric field is electric force per unit of charge or
[tex]E=\frac{F}{q}[/tex]
F is electric force calculated as:
[tex]F=\frac{kQq}{r^{2}}[/tex]
Electric field will be:
[tex]E=\frac{kQq}{qr^{2}}[/tex]
[tex]E=\frac{kQ}{r^{2}}[/tex]
where k is coulomb constant and is approximately [tex]9.10^{9}\frac{Nm^{2}}{C^{2}}[/tex]
Changing units to match the constant:
38pC = [tex]38.10^{-12}[/tex]C
17cm = [tex]17.10^{-2}[/tex]m
So, electric field for bees in the given conditions is:
[tex]E=\frac{9.10^{9}.38.10^{-12}}{(17.10^{-2})^{2}}[/tex]
[tex]E=\frac{342.10^{-3}}{289.10^{-4}}[/tex]
E = 11.8N/C
The smallest external electric field to which bees nay be sensitive is 11.8N/C