Question

The volume of a rectangular tank is (12xcube+ 20xsquare- x-6). If the length is (3x + 2) & height is ( 2x + 3).
find the width of the tank.​

Answer 1

Answer:

(2x-1)

Step-by-step explanation:

$Volume\ of\ the\ tank\ = 12x^3+20x^2-x-6\\Length\ of\ the\ tank\ = 3x+2\\Breadth\ of\ the\ tank\ = 2x+3\\Height\ of\ the\ tank\ = h\\We\ know\ that\ volume\ of\ a\ cuboid\ = lbh\\Hence, h= Volume / lb\\Here,\\Height\ of\ the\ tank= \frac{(12x^3+20x^2-x-6)}{(3x+2)(2x+3)} \\By\ factorising\ the\ volume\ through\ synthetic\ division\, \\we get,\\(12x^3+20x^2-x-6)= (3x+2)(2x+3)(2x-1)\\Hence, height= (2x-1)$