What is the value of the expression (3a-b)/(6(b+a)) when a = 4 and b = -2? Show your work to support your answer.

please be specific

Respuesta :

Answer:

[tex]1\frac{1}{6}[/tex] or 1.166 Repeating

Step-by-step explanation:

This is a very simple equation!

First you write it out

[tex]\frac{3a-b}{6(b+a)}[/tex]

Now you plug in your values.

a = 4

b= -2

So.

[tex]\frac{3(4) - (-2)}{6(-2+4)}[/tex]

Now, follow PEMDAS

3 (4) = 12

12 - (-2) is the same as 12+2 Which equals 14

Now you have...

[tex]\frac{14}{6(-2+4)}[/tex]

-2 + 4 = 2

6 (2) = 12

Final Fraction is

[tex]\frac{14}{12}[/tex]

Which can be reduced to

[tex]\frac{7}{6}[/tex]

or

1.166 (repeating)

Hope this helps!