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2. A jet plane is traveling at 0.06 km/sec when its wheels leave the runway at 0.09 km/sec 8.0 seconds later. What is its acceleration during landing? op​

Respuesta :

Farouh

Answer:

13.5 km/h/sec

Explanation:

  • change the km/sec to km/h by multiplying by 3600; so the 0.06 km/sec will be 216 km/h, and the 0.09 km/sec will be 324 km/h
  • a= ∧v/∧t = (324 - 216) / 8.0 = 13.5

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