Question

A ball initially at rest rolls down a hill and has an acceleration of 3.3 m/s2. If it accelerates for 7.5 s, how many meters will it move during this time?

Answer 1

The distance the ball rolls is given by

x = 1/2 a t²

so that

x = 1/2 * (3.3 m/s²) * (7.5 s)² = 92.8125 m ≈ 93 m