Question

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $75. For one performance, 15 advance tickets and 35 same-day tickets were sold. The total amount paid for the tickets was $1825. What was the price of each kind of ticket?

Answer 1

Answer:

The price of the advance ticket is $40 and the price for the same-day ticket is $35.

Step-by-step explanation:

From the information given, you can write the following equations:

x+y=75 (1)

15x+35y=1825 (2), where:

x is the price for advance tickets

y is the price for same-day tickets

First, you can isolate y in (1)

y=75-x (3)

Then, you have to replace (3) in (2):

15x+35(75-x)=1825

15x+2625-35x=1825

2625-1825=35x-15x

800=20x

x=800/20

x=40

Finally, you can replace the value of x in (3) to find y:

y=75-40

y=35

According to this, the answer is that the price of the advance ticket is $40 and the price for the same-day ticket is $35.