Question

A fish tank holds 180 gallons of water and is leaking at a rate of 8 gallons per day. A second fish tank holds 160 gallons of water and is leaking at a rate of 6 gallons per day. At how many days will the two fish tanks have the same amount of water?

Answer 1

Answer:

10 days

Step-by-step explanation:

$180 - 8x = 160 - 6x$

subtract 160 from both sides and add 8x to both sides

$20 = 2x$

divide both sides by 2

$x = 10$