Line p is represented by the equation 2x-y=-5. If line r passes through the point (6,4) and is perpendicular to line p, what is the equation of line r?

Respuesta :

Answer:

[tex]y = -\frac{1}{2}x + 7[/tex]

Step-by-step explanation:

Given

[tex]2x - y = 5[/tex]

[tex]Point = (6,4)[/tex]

Required

Determine the equation of perpendicular line, r

First we need to determine the slope of the given equation

[tex]2x - y = 5[/tex]

Make y the subject:

[tex]y = 2x - 5[/tex]

The general form of an equation is:

[tex]y = mx + b[/tex]

Where:

[tex]m = slope[/tex]

By comparison;

[tex]m = 2[/tex]

Since both lines are perpendicular:

We have:

[tex]m_1 = -1/m[/tex] to calculate the slope of the perpendicular line

[tex]m_1 = -\frac{1}{2}[/tex]

Equation of the line can be solved using:

[tex]y - y_1 = m(x - x_1)[/tex]

Where

[tex](x_1,y_1) = (6,4)[/tex]

[tex]m = m_1 = -\frac{1}{2}[/tex]

So: the equation becomes

[tex]y - 4 = -\frac{1}{2}(x - 6)[/tex]

[tex]y - 4 = -\frac{1}{2}x + 3[/tex]

Solve for y

[tex]y = -\frac{1}{2}x + 3 + 4[/tex]

[tex]y = -\frac{1}{2}x + 7[/tex]

Hence:

The required equation is

[tex]y = -\frac{1}{2}x + 7[/tex]