Answer:
– 376.56 J
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 45 g
Specific heat capacity (C) = 4.184 J/gºC
Initial temperature (T1) = 25 °C
Final temperature (T2) = 23 °C
Heat released (Q) =..?
Next, we shall determine the change in the temperature of the water. This can be obtained as follow:
Initial temperature (T1) = 25 °C
Final temperature (T2) = 23 °C
Change in temperature (ΔT) =.?
Change in temperature (ΔT) = T2 – T1
Change in temperature (ΔT) = 23 – 25
Change in temperature (ΔT) = – 2 °C
Finally, we shall determine the heat released as follow:
Mass (M) = 45 g
Specific heat capacity (C) = 4.184 J/gºC
Change in temperature (ΔT) = – 2 °C
Heat released (Q) =..?
Q = MCΔT
Q = 45 × 4.184 × (– 2)
Q = – 376.56 J
Therefore, the heat released is – 376.56 J.
Note: The negative sign indicates that heat is released to the surrounding.
