Question

The arrows on two spinners are spun one time. The first spinner is divided equally into the colors red, blue, green, and yellow. The second spinner is
divided equally into the numbers 1, 2, 3, and 4. All possible outcomes are shown in the table.
Red Blue Green Yellow
1 (R1) B.1) (G1) (Y,1)
2 (R.2) (B2) (G2) (Y,2)
3 (R3) (B3) (B3) (4,3)
4 (R,4) (B,4) (6,4) (Y,4)
What is the nrnhability that the first spinner lands on red or the second spinner lands on an even number?

Answer 1

Answer:

I chose 5/8

Step-by-step explanation:

Got a high score

Answer 2

Using it's concept, it is found that there is a 0.125 = 12.5% probability that the first spinner lands on red or the second spinner lands on an even number.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem:

• For the first spinner, one out of the four sections are red, hence P(A) = 1/4.

• For the second spinner, two out of the four sections are even numbers, hence P(B) = 2/4.

Since the spinners are independent, the probability of both events is given by:

P(A and B) = P(A) x P(B) = 1/4 x 2/4 = 1/8 = 0.125 = 12.5%.

0.125 = 12.5% probability that the first spinner lands on red or the second spinner lands on an even number.

More can be learned about probabilities at https://brainly.com/question/14398287

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