Answer:
x = [tex]\frac{1}{4}[/tex]
y = [tex]\frac{3}{4}[/tex]
z = 0
Step-by-step explanation:
You first need to solve for a variable, it won't be as easy as x = 3, you are looking to replace a variable with another equation.
For example, the second equation, 4y-z=3, I can either solve for y or z. It won't be a numerical value but it will get you a step closer.
4y-z=3
4y=z+3
y = [tex]\frac{z}{4} +\frac{3}{4}[/tex]
Then you are able to use substitution to negate one of the variables and solve for the other two variables. I won't type that but I think you get the idea.
