Question

Simplify completely 4 m cubed over 3 m squared n times 9 n squared over 30 m squared n squared.

Answer 1

$\frac{4m ^{3} }{3m ^{2} n}* \frac{9n ^{2} }{30m^{2}n^{2} } = \\ \frac{36m ^{3} n ^{3} }{90m ^{4}n ^{3} }$
After that 36 and 90 can both be divided by 18 and:
m^3/m^4 = 1/m;  n^2/n^3 = 1/n;
... = $\frac{2}{5mn}$
Answer:  4 )