Answer:
B
Step-by-step explanation:
We have the two functions:
[tex]f(x)=\frac{x}{2}-2\text{ and } g(x)=2x^2+x-3[/tex]
And we want to find:
[tex](f+g)(x)[/tex]
This is the same thing as:
[tex]=f(x)+g(x)[/tex]
Let's substitute them for their respective equations. This yields:
[tex]=(\frac{x}{2}-2})+(2x^2+x-3)[/tex]
Combine like terms:
[tex]=(2x^2)+(\frac{x}{2}+x)+(-2-3)[/tex]
Add:
[tex]=2x^2+\frac{3}{2}x-5[/tex]
So, our answer is B.
And we're done!