Question

If (8,0) is on y=bx+x^2, what is the least value of the function?

Answer 1

Greetings from Brasil...

(8; 0) ⇔ (X; Y) ⇒ so, according to the statement of the question, when X = 8 we have a Y = 0.

Y = bX + X²

(8; 0) ⇒ X = 8 and Y = 0

0 = b · 8 + 8²

0 = 8b + 64

8b = - 64

b = - 64/8

b = - 8

Then

Y = X² - 8X

Answer 2

The minimum value or least value of the function is -16 at x = 4 after plotting the graph.

What is a quadratic equation?

Any equation of the form $\rm ax^2+bx+c=0$ where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

$\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}$

We have:

(8,0) is on y=bx+x²

Plug x = 8 and y = 0

0 = 8b + 64

b = -8

y = -8x + x²

Thus, the minimum value or least value of the function is -16 at x = 4 after plotting the graph.

Learn more about quadratic equations here:

brainly.com/question/2263981

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