Question

Find the distance between the two points rounding to the nearest tenth (if necessary),
(-1,-6) and (8,6)

Answer 1

Answer:

The answer is 15 units

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} }$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-1,-6) and (8,6)

The distance between them is

$d = \sqrt{( { - 1 - 8})^{2} + ({ - 6 - 6})^{2} } \\ = \sqrt{ ({ - 9})^{2} + ( { - 12})^{2} } \\ = \sqrt{81 + 144} \\ = \sqrt{225} \: \: \: \: \: \: \: \: \: \: \\ = 15 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

We have the final answer as

15 units

Hope this helps you

Answer 2

Step-by-step explanation:

Hey there!

The given points are; (-1-6) and (8,6).

Now, Using distance formula we get;

$d = \sqrt{ {(x2 - x1)}^{2} + ( {y2 - y1)}^{2} }$

Put all values.

$d = \sqrt{ {(8 + 1)}^{2} + ( {6 + 6)}^{2} }$

Simplify it to get answer.

$d = \sqrt{ {(9)}^{2} + ( {12)}^{2} }$

$d = \sqrt{81 + 144}$

$d = \sqrt{225}$

d = 15 units.

Therefore, the distance between two points is 15 units.

Hope it helps...